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katrin2010 [14]
3 years ago
8

Which system of equations can be used to find the roots of the equation 4 x Superscript 5 Baseline minus 12 x Superscript 4 Base

line + 6 x = 5 x cubed minus 2 x?
StartLayout Enlarged left-brace 1st Row y = negative 4 x Superscript 5 Baseline + 12 x Superscript 4 Baseline minus 6 x 2nd row y = 5 x cubed minus 2 x EndLayout
StartLayout Enlarged left-brace 1st Row y = 4 x Superscript 5 Baseline minus 12 x Superscript 4 Baseline + 5 x cubed + 4 x 2nd row y = 0 EndLayout
StartLayout Enlarged left-brace 1st row y = 4 x Superscript 5 Baseline minus 12 x Superscript 4 Baseline + 6x 2nd row y = negative 5 x cubed + 2 x EndLayout
StartLayout Enlarged left-brace 1st row y = 4 x Superscript 5 Baseline minus 12 x Superscript 4 Baseline + 6x 2nd row y = 5 x cubed minus 2 x EndLayout
Mathematics
1 answer:
ehidna [41]3 years ago
3 0

Answer:

D. on Edg 2020

Step-by-step explanation:

You are welcome, I helped better than that other guy!!!

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One tank is filling at the rate of 3/4 gallon / 2/3 minute a second tank is filling at the rate of 3/8 gallon per 1/2 minute whi
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\bf \cfrac{\quad \stackrel{gallons}{\frac{3}{4}}\quad }{\stackrel{minutes}{\frac{2}{3}}}\implies \cfrac{3}{4}\cdot \cfrac{3}{2}\implies \cfrac{9}{8}~g/m
\\\\\\
\cfrac{\quad \stackrel{gallons}{\frac{3}{8}}\quad }{\stackrel{minutes}{\frac{1}{2}}}\implies \cfrac{3}{8}\cdot \cfrac{2}{1}\implies \cfrac{3}{4}~g/m\\\\
-------------------------------

\bf \cfrac{3}{4}\cdot \cfrac{2}{2}\implies \cfrac{6}{8}\quad \textit{clearly then }\cfrac{9}{8}\textit{ is larger than }\cfrac{6}{8}
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\stackrel{\stackrel{tank's~volume}{gallons}}{y}=\cfrac{9}{8}\stackrel{minutes}{x}
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