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2 years ago

What is the approximate value of a local maximum for the polynomial

Mathematics

1 answer:

statuscvo [17]2 years ago

8 0

Answer:

D) 2.5

Aaliyah- ツ

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The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.71 millimeters and a standard deviat

Harlamova29_29 [7]

Answer:

The bolts with diameter less than 5.57 millimeters and with diameter greater than 5.85 millimeters should be rejected.

Step-by-step explanation:

We have been given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.71 millimeters and a standard deviation of 0.08 millimeters.

Let us find the sample score that corresponds to z-score of bottom 4%.

From normal distribution table we got z-score corresponding to bottom 4% is -1.75 and z-score corresponding to top 4% or data above 96% is 1.75.

Upon substituting these values in z-score formula we will get our sample scores (x) as:

$z=\frac{x-\mu}{\sigma}$

$-1.75=\frac{x-5.71}{0.08}$

$-1.75*0.08=x-5.71$

$-0.14=x-5.71$

$-0.14+5.71=x-5.71+5.71$

$5.57=x$

Therefore, the bolts with diameters less than 5.57 millimeters should be rejected.

Now let us find sample score corresponding to z-score of 1.75 as upper limit.

$1.75=\frac{x-5.71}{0.08}$

$1.75*0.08=x-5.71$

$0.14=x-5.71$

$0.14+5.71=x-5.71+5.71$

$5.85=x$

Therefore, the bolts with diameters greater than 5.85 millimeters should be rejected.

7 0

3 years ago

Help please will mark Brainlyest plz help quickly

Helga [31]

Answer: 28*63

Step-by-step explanation:

- If first you want the answer, you must divide and then you would get 63.

- Then you take 63 and multiply 28 and you'll get 1,764

Hope I was able to help.

(For question 27)

8 0

3 years ago

The irregular figure on the left has been decomposed into the figures on the right.

shusha [124]

Answer:

The density of the material must be at least 1.5 g/cm³.

Step-by-step explanation:

7 0

3 years ago

What are the solutions to the quadratic equation -2x^2 + 6x + 3 = 0?

mario62 [17]

For this, we will be using the quadratic formula, which is $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$ , with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: $x=\frac{-6+/-\sqrt{6^2-4*(-2)*3}}{2*(-2)}$

Firstly, solve the multiplications and the exponents: $x=\frac{-6+/-\sqrt{36+24}}{-4}$

Next, do the addition: $x=\frac{-6+/-\sqrt{60}}{-4}$

Next, your equation will be split into two: $x=\frac{-6+\sqrt{60}}{-4},\frac{-6-\sqrt{60}}{-4}$ . Solve them separately, and your answer will be $x=-0.436,3.436$

5 0

3 years ago

If ƒ(x ) = x^2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)]^2.<br><br> 1<br> 2<br> 9

stepladder [879]

I think that the answer would be 2 if I am right

5 0

3 years ago

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