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OLga [1]
3 years ago
12

Why do you sometimes have only one multiplication sentence for an array

Mathematics
1 answer:
taurus [48]3 years ago
7 0

Arrays are useful models for multiplication which can be used in a variety of ways, ranging from highly structured lessons to games and open investigations. An array is formed by arranging a set of objects into rows and columns. Each column must contain the same number of objects as the other columns, and each row must have the same number as the other rows.


The following array, consisting of four columns and three rows, could be used to represent the number sentence 3 x 4 = 12.

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Y=-x^2-14x-59<br> pls help
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3 years ago
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A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
3 years ago
Do not round intermediate calculations. round your answers to two decimal places. a. define a random variable number of times th
navik [9.2K]

Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours

547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000

x = no. of times owner-occupied units had a water supply stoppage.

<h3>What is the probability at x =0?</h3>

P(x=0) = 547000/14770000

P(x=0) = 0.0370

Similarly, we have at x=1

P(x=1) = 5012000/14770000

P(x=1) = 0.3393

P(x=2) = 6110000/14770000

P(x=2) = 0.4137

P(x=3) = 2544000/14770000

P(x=3) = 0.1722

P(x=4) = 557000/14770000

P(x=4) = 0.0378

x           f(x)

0             0.0370

1              0.3393

2         0.4137

3              0.1722

4         0.0378

Total     1

Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

To learn more about the probability distribution visit:

brainly.com/question/24756209

#SPJ1

7 0
2 years ago
PLS HELP 20 POINTS
bezimeni [28]

Answer:

missing number=81

Step-by-step explanation:

you are multiplying by three.

27×3=81

4 0
3 years ago
Read 2 more answers
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