Answer:
-8a -8b + 8c
Step-by-step explanation:
-8(a + b - c)
-8 x a is -8a
-8 x b is -8b
-8 x -c is 8c
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<u>-8a -8b + 8c</u>
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I Hope That This Helps! :)
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Answer:
hypotenuse is 22.47 m
Step-by-step explanation:
The length of both legs of a right angle triangle are 8m and 21 m
We need to find the hypotenuse
To find hypotenuse we use Pythagorean theorem
Hypotenuse is AC and other two legs are AB and BC

Hypotenuse ^2 = 8^2 + 21^2
hypotenuse = 
= 
= 
= 22.47
So the length of the hypotenuse is 22.47 m


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
- BCD is an isosceles right triangle , right angled at D
- ABC is an equilateral triangle


❒ Sum of all angles is 180° , since it is an equilateral triangle all the three angles would be same





(Isosceles triangle)









I believe it should be 36.00$
Since the court is 9 meters wide we would have to multiply that by 4 because each meter is 4$