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2 years ago

Find the value 5x+2 x=3

Mathematics

2 answers:

igor_vitrenko [27]2 years ago

8 0

Answer:

Step-by-step explanation:

you multiply 5 and x and you get 15 plus 2 equals 17

Mashutka [201]2 years ago

5 0

Plug x=3 into the equation:
5(3)+2
And simplify:
15+2
17

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Jeremy traveled 345 miles to visit his cousin in north carolina. if he traveled at a rate of 60 miles per hour, how long did the

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The trip took 5 hours and 45 mins

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3 years ago

Evaluate the question

mylen [45]

Answer:

A) 5/6

B) -67/30 (or) -2 7/30

A) -9/2 (or) -4 1/2

Step-by-step explanation:

A) 2/3(5)-5/2=3 1/3-5/2 = 10/3-5/2 = 20/6-15/6= 5/6

B) 2/3(2/5)-5/2= 4/15-5/2 = 8/30-75/30 = -67/30

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3 years ago

A solid figure with flat faces

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3 years ago

Read 2 more answers

How many different four-person relay teams can be chosen from eight students

aliina [53]

Slot method

8 optionns n 1st slot
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6 options in 3rd slot
5 options in 4th slot

8*7*6*5=1680 ways

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4 years ago

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0

3 years ago