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bezimeni [28]
3 years ago
14

Can you answer this?

Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0
Answer what? There is no question to answer
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Someone help, math quiz
Serggg [28]
So your gonna Multiply each term in the first parentheses by each term in the second parentheses “ -5x5-5i-5x2i-2ix i ” than multiply the numbers “ -25 -5i -5x2i -2ixi ” that’s your answer!
8 0
2 years ago
What is1/12+7/9. I need help.
Katarina [22]
You have to make them have their least common denominator to add or subtract, in this case 36.
Multiply 1/12 by 3, to get the denominator 36: 3/36.
Multiply 7/9 by 4, to get the denominator 36: 28/36.
Now add the numerators: 3+28=31, 31/36 is as simplified as possible so your answer is 31/36 :) I hope this helps :)
7 0
3 years ago
20 is what percent of 32 <br> Write as an equation
AlladinOne [14]
20% of 32= 6.4



20% x 32

20 /100 x 32
Reduce the fraction
1 /5× 32
=32/5
=6.4
8 0
3 years ago
Using the work shown on the left, What is the cubed root of 4/ the square root of 2 in simplest radical form
krek1111 [17]

Answer:

⁶√2

Step-by-step explanation:

∛4 = (2^2)^1/3 = 2^2/3

So ∛4 / √2

= 2^2/3 / 2^1/2

= 2^1/6

= ⁶√2

5 0
3 years ago
How much chromium-51 will be left after 7 months?
Makovka662 [10]

Answer:

It seems there's more information in you question that you haven't posted.

7 months = 7 * (365/12) = 213 days

The half-life of chromium 51 is 27.7 days.

After 7 months, chromium 51 will have undergone 7.69 half-lives.

To solve for the ending amount we'll use the formula:

Ending Amount = Beginning Amount / 2^n where 'n' = # of half-lives

We'll say the beginning amount =1

Ending Amount = 1 / 2^7.69

Ending Amount = 0.0048426082

Basicaly if you started with 1 gram of chromium 51, after 7 months you would have 0.0048426082 grams.

Source: https://www.1728.org/halflife.htm

Step-by-step explanation:

6 0
2 years ago
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