Let the marked prize of the TV be x .
We have SP = MP - Discount
<em>Hence </em><em>,</em><em> </em><em>T</em><em>he </em><em>marked</em><em> </em><em>prize</em><em> </em><em>of </em><em>the </em><em>TV </em><em>is </em><em>₹</em><em>2</em><em>0</em><em>,</em><em>2</em><em>5</em><em>0</em><em> </em><em>.</em>
<em>Hope </em><em>it </em><em>helps </em><em>~</em><em> </em>
Answer:
Step-by-step explanation:
You know how subtraction is the <em>opposite of addition </em>and division is the <em>opposite of multiplication</em>? A logarithm is the <em>opposite of an exponent</em>. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.
We know that ; as a logarithm, the <em>exponent</em> gets moved to its own side of the equation, and we write the equation like this: , which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."
One historical quirk: because we use the decimal system, it's assumed that an expression like uses <em>base 10</em>, and you'd interpret it as "What power do I raise 10 to to get 1000?"
The expression means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is .
(If we wanted to, we could also solve this: , so )
"300 K and 2 atm" is the condition among the conditions given in the question that you can <span>expect helium gas to deviate most from ideal behavior. The correct option among all the options that are given in the question is the second option or option "b". I hope the answer has helped you.</span>
Answer:
i only know it is c and e but dont know about a and b
Step-by-step explanation:
Answer:
0.336
Step-by-step explanation:
Use binomial probability:
P = nCr p^r q^(n-r)
where n is the number of trials,
r is the number of successes,
p is the probability of success,
and q is the probability of failure (1-p).
Here, n = 8, r = 7, p = 0.8, and q = 0.2.
P = ₈C₇ (0.8)⁷ (0.2)⁸⁻⁷
P = 0.336