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Grace [21]
3 years ago
12

Solve for perimeter and area of rectangle

Mathematics
1 answer:
agasfer [191]3 years ago
3 0
U would find the distance between the each point, though since the rectangle has two pairs of congruent sides you only need to solve for two and add/multiply accordingly using p = 2l + 2w and a = lw . my phones a little broken so I can’t see the pic/solve exactly but u could use the distance formula to find the lengths of the lines. hope this helped
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Do you guys know which coordinates im supposed to graph on here?
nadezda [96]

Answer:

SOLVE FOR Y

graph y= 2x + 2

sp graph the points

(0,2) and then (1,4)

connect the points and extend the line.

Step-by-step explanation:

add 2x to both sides

-2x+y=2

+2x     +2x

y= 2+2x

reverse

y= 2x+2

3 0
3 years ago
What is the slope of the line 1/2y=-5x-37
DIA [1.3K]

Answer:

Slope = - 10

Step-by-step explanation:

y=mx+n, m=slope

1/2y=-5x-37 /*2

y=-5*2x-37*2

y=-10x-74

Slope =- 10

4 0
3 years ago
Enter decimal numbers in the boxes to complete the ordered pair that locates point Q on the coordinate plane.
stiv31 [10]

Answer:

I know for sure that it is 1.5, -1.5

3 0
3 years ago
A washer and a dryer cost $595 combined. The washer costs $55 less than the dryer. What is the cost of the dryer?
JulijaS [17]

Answer:Oh, be very careful about the "$87."

 

Let the dryer cost x.

Then, the washer costs (x+87)

 

Together, they cost  (x) + (x+87) = 787

        2x+87 = 787

           2x = 700           [subtract 97 from both sides]

            x = 350             [divide both sides by 2]

 

The dryer cost $350.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
How much more interest is owed on $900 for 9 months then for 6 months? 6 months = 2.4% rate 9 months = 2.9% rate
stiv31 [10]
Keeping in mind that 6 months is not even a year, since there are 12 months in a year, then 6 months is really 6/12 years, and 9 months is 9/12 years, then


\bf ~~~~~~ \textit{Simple Interest Earned on 9 months}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$900\\
r=rate\to 2.9\%\to \frac{2.9}{100}\to &0.029\\
t=years\to \frac{9}{12}\to &\frac{3}{4}
\end{cases}
\\\\\\
I=900(0.029)\left( \frac{3}{4} \right)\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned on 6 months}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$900\\
r=rate\to 2.4\%\to \frac{2.4}{100}\to &0.024\\
t=years\to \frac{6}{12}\to &\frac{1}{2}
\end{cases}
\\\\\\
I=900(0.024)\left( \frac{1}{2}\right)

check their difference, that much.
6 0
3 years ago
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