9514 1404 393
Answer:
- sin(Ф) = (4/41)√41; csc(Ф) = (√41)/4
- cos(Ф) = (5/41)√41; sec(Ф) = (√41)/5
- tan(Ф) = 4/5; cot(Ф) = 5/4
Step-by-step explanation:
The mnemonic SOH CAH TOA can help you with three of the functions. Then you need to remember the relations between those and the other three.
Tan = Opposite/Adjacent
tan(Ф) = 4/5
This suggests you can draw a triangle like the one attached that has adjacent side 5 and opposite side 4. Then hypotenuse can be found from the Pythagorean theorem:
AC² = AB² +BC² = 5² +4² = 41
AC = √41 . . . . . hypotenuse
Then the other trig functions are ...
Sin = Opposite/Hypotenuse
sin(Ф) = 4/√41 = (4/41)√41
Cos = Adjacent/Hypotenuse
cos(Ф) = 5/√41 = (5/41)√41
And the reciprocal functions are ...
csc(Ф) = 1/sin(Ф) = (√41)/4
sec(Ф) = 1/cos(Ф) = (√41)/5
cot(Ф) = 1/tan(Ф) = 5/4
Answer:
D
Step-by-step explanation:
Answer:
Step-by-step explanation:
x^2-1=0
Add 1 to both sides of the equation.
x^2=
1
Take the square root of both sides of the equation to eliminate the exponent on the left side.
x
=
±
√
1
Any root of 1 is x
=
±
1
First, use the positive value of the ±
to find the first solution.
x=
1
Next, use the negative value of the ±
to find the second solution.
x
=
−
1
The complete solution is the result of both the positive and negative portions of the solution.
x
=
1
,
−
1
Answer:
f(9) = - 2/3
Step-by-step explanation:
I don't really know how to answer those but I think I am right
Let smaller no be x and bigger be y
- x+y=39--(1)
- 3x=y+81
- y=3x-81
- y=3(x-27)--(2)
Put it in eq(1)
- x+3(x-27)=39
- x+3x-81=39
- 4x=81+39
- 4x=120
- x=30
Now
The numbers are 9 and 30