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ElenaW [278]
2 years ago
12

Help pls!! :< I'll give brainliest!

Mathematics
1 answer:
stich3 [128]2 years ago
4 0
It is the last one because if you go 3 left you have to change the sign to a positive (but it is still a negative) and the 2 remain the same sign so it’s h(x-3)-2
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B is the midpoint of AC and E' is the midpoint of BD. If A(-9,-4), C(-1, 6), and E(-4,-3), find the coordinates of D.
Ipatiy [6.2K]
The coordinates for D are (-4, -7)

First we must locate point B as it is vital to finding the midpoint of BD. To do this, we take the average of the endpoints AC since B is its midpoint. 

x values = -9 + 1 = -8
Then divide by 2 for the average -8/2 = -4

y values = -4 + 6 = 2
Then divide by 2 for the average 2/2 = 1

Therefore B must be (-4, 1)

Now we know the values of E must be the average of B and D. So we can write equations for each coordinate since we know they are averages. 

x - values = (Bx + Dx)/2 = Ex
(-4 + Dx)/2 = -4 ---> multiply both sides by 2
-4 + Dx = -8 ---> add -4 to both sides
Dx = -4

y - values = (By + Dy)/2 = Ey
(1 + Dy)/2 = -3 ---> multiply both sides by 2
1 + Dy = -6 ---> subtract 1 from both side
Dy = -7

So the coordinates for D must be (-4, -7)
5 0
3 years ago
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Write the equation that represents the graph to the left. PLEASE HURRY!!!! helpppp
natita [175]

Answer:

y=5x

Step-by-step explanation:

Tell me if you need an explanation.

If this answer has helped you, please mark this as brainliest.

6 0
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How can factors help you find a common denominater? <br>PLEASE HELP!!!!!!!!!
Gekata [30.6K]
They can help you find a common denominator by the bottoms of each fraction if the top ones don't have the same denominator.
8 0
3 years ago
What is the value of x in the figure ?
morpeh [17]

Step-by-step explanation:

2x+15= 145°

( vertically opposite angles)

2x=145-15 = 130

x =  \frac{130}{2}

x = 65

3 0
3 years ago
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nasty-shy [4]
If that's an addition sign, then b=-35.
If it's a division sign, then b=-150

Sorry I can't see which it is! Hope this helped though :)
Good luck!
3 0
3 years ago
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