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mote1985 [20]
3 years ago
9

NEED HELP IN NEED THE ANSWER BY TO NIGHT PLE.

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Answer:

Step-by-step explanation:

1 sandwich is 6.25 (because 31.25/5)

2 sandwiches is 12.5

3 sandwiches are 18.75

4 sandwiches are 25

5 sandwiches are 31.25

6 sandwiches are 37.5

Amy - 8s + 12

8(6.25) +12 = 62

Amy paid $62.

Bob - 8(s + 2)

8(6.25 + 2) = 66

Bob pays $66.

Cathy - 4(2s + 3)

4(2 x 6.25 + 3) = 62

Cathy paid $62.

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(1 point) Consider the function f(x)=2x3−9x2−60x+1 on the interval [−4,9]. Find the average or mean slope of the function on thi
OlgaM077 [116]

Answer: c = 4.97 and c = -1.97

Step-by-step explanation: <u>Mean Value Theorem</u> states if a function f(x) is continuous on interval [a,b] and differentiable on (a,b), there is at least one value c in the interval (a<c<b) such that:

f'(c) = \frac{f(b)-f(a)}{b-a}

So, for the function f(x) = 2x^{3}-9x^{2}-60x+1 on interval [-4,9]

f'(x) = 6x^{2}-18x-60

f(-4) = 2.(-4)^{3}-9.(-4)^{2}-60.(-4)+1

f(-4) = 113

f(9) = 2.(9)^{3}-9.(9)^{2}-60.(9)+1

f(9) = 100

Calculating average:

6c^{2}-18c-60 = \frac{100-113}{9-(-4)}

6c^{2}-18c-60 = -1

6c^{2}-18c-59 = 0

Resolving through Bhaskara:

c = \frac{18+\sqrt{1740} }{12}

c = \frac{18+41.71 }{12} = 4.97

c = \frac{18-41.71 }{12} = -1.97

<u>Both values of c exist inside the interval [-4,9], so both values are mean slope: c = 4.97 and c = -1.97</u>

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