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Murrr4er [49]
3 years ago
13

Find the area of cross section,the lateral surface area,the total surface area and volume of the following prisms.​

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:

don't

Step-by-step explanation:

please send me only

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A track has the shapes shown. what is the perimeter ?
USPshnik [31]
Break this problem down first. You have two lines each with length of 5. You also have two halves of a circle, combine them to get a full circle with a radius of 2. The formula to find the perimeter of a circle is
2\pi \times r
and this gives a perimeter of 12.566 for the circle. Add this to your sides and you get a total of 22.566 which is answer B
4 0
3 years ago
The sentence "the length of a rectangle is 6 feet more than the width" can be translated as / = 6 + w.
matrenka [14]

Answer:

true

Step-by-step explanation:

if the width is w and the length is l then 6 more than the width is w+6 and that is equal to the length so l = w+6

7 0
3 years ago
Explain how you can use a number line to show that 5/8 is greater than 3/8
vladimir2022 [97]


You can start by drawing a number line and labeling it with eighths. ( 1/8, 2/8, etc.) Then you can place a dot on 3/8 and 5/8. From there, it's clear to see that 5/8 is greater than 3/8.

6 0
3 years ago
Read 2 more answers
Could someone help me fast, ill mark as brainliest, and no links bc ill report you for that
Masteriza [31]
D is correct I believe since the values has an outlier it automatically gets rid of using mean. The dots are somewhat symmetrical. And for something to be skewed the dots are to be “connected”
4 0
3 years ago
find the area of a circke with a radius of 9 mm. round to the nearest tenth. use 3.15 or 22/7 for Pi.​
GREYUIT [131]

Answer:

254.3 mm^2

Step-by-step explanation:

Area of a circle: A = π*r^2

π (pi) = 3.14

r (radius) = 9 mm

Substitute 3.14 for pi and 9 for radius:

A = π*r^2

A = 3.14*9^2

A = 3.14*81

A = 254.34 mm^2

Round to the nearest tenth:

254.34 ==> 254.3

Therefore, our final answer is 254.3 mm^2

Hope this helps!

6 0
2 years ago
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