Maija is bicycling north on a straight path. She bicycles for

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago

If the side length of a square pyramid is triple and the slant height is divided by 5 what would be the formula to find the modi

valentina_108 [34]

If the original side length is "s" and the original slant height is "h", the original surface area is
.. S = (base area) +(lateral area)
.. S = s² +(1/2)*(4s)*h
.. S = s(s +2h)

Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have
.. S' = (3s)(3s +2h/5)
.. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)

_____
Of course, in terms of the modified dimensions, the formula is the same:
.. S' = s'(s' +2h')

5 0

3 years ago

Komok [63]

Answer:

42.7 cm sq.

Step-by-step explanation:

small/large = 16 / 122

16/122 = S / 56

S = 56 * (16/122) = 7.34...

however not in the choice

ah ha..

You meant : 12.2 sq. cm : 16 sq. cm = small / large

so 12.2 / 16 = S / 56 cm

S = 42.7 sq. cm

8 0

4 years ago

I need help with this one plz! (marking BRAINLIST) :)

FinnZ [79.3K]

Answer:

x=22

Step-by-step explanation:

the triangle in which x is in is an equilateral triangle.

44 is an exterior angle to that triangle.

an exterior angle is always equal to tbe sum of the opposite 2 interior angles.

because that triangle is equilateral

x =44 ÷ 2

x=22

5 0

3 years ago

Select what would happen to your 1) taxable income and 2) tax liability when you are able to claim a deduction such as student l

Vinil7 [7]

When you are able to claim a deduction such as student loan interest would taxable income would be lower and your tax liability would go higher. The liability would increase since a loan is a debt. Hope this answers the question. Have a nice day.

3 0

3 years ago