Given:
Point (7,12) is rotated 1260° counterclockwise about the origin.
To find:
The x-coordinate of the point after this rotation.
Solution:
If a point is rotated 360 degrees then its coordinates remains unchanged.
If a point is rotated 180 counterclockwise about the origin degrees, then
We know that,
After 
rotation the coordinates of points remains same, i.e., (7,12). So, after that (7,12) is rotated 180° counterclockwise about the origin.
The point (7,12) becomes (-7,-12) after rotation of 1260° counterclockwise about the origin.
Therefore, the x-coordinate of the required point is -7.
Y = mx + c, where m is your gradient and c is your y intercept.
If the line is perpendicular to the line y = 3x - 5, the line's gradient = -(1/3) as when it comes to perpendicular bisector, m1/m2 = -1
y = -(1/3)x + C
To find C sub in x=2 and y=2 as it goes through (2,2)
2 = -(1/3)2 + C
2 = -(2/3) + C
2 + 2/3 = C
C = 8/3
There your equation of a line is
y = -(1/3)x + 8/3
What is asked in the problem is simply the volume of the solid rubber ball. The volume of sphere given the diameter may be calculated by,
V = πd^3 / 6
Substituting the given value of diameter,
V = (π x 3³) / 6 = 9π/2 or 14.14
Thus, one needs approximately 14.14 in³ of material.
The answer is 6 to your question, but why does my answer have to be at least 20 characters long?
