Answer:
The width of the scale model is 33 inches.
Step-by-step explanation:
This question is solved making a relation with the scale model.
In the scale, 3 inches are worth 11 real feet.
The actual width of the building is 121 feet, so we find it's scale by a rule of three.
3 inches - 11 feet
x inches - 121 feet
Simplifying by 3, both sides
The width of the scale model is 33 inches.
Consider the given triangles.
Given:
ASA congruence criterion states that if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.
AAS congruence criterion states that if two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.
Consider the first part:
1. In triangles ABC and QPT
If we take along with the given condition.
Then the triangles are congruent by ASA congruence criterion.
2. If we take and
along with the given condition.
Then the triangles are congruent by ASA congruence criterion.
3. As,,
and
, so the triangles can not be congruent.
4. If we take and
along with the given condition.
Then the triangles are congruent by AAS congruence criterion.
5. If we take AC=TQ=3.2 and CB=QP=3.2 along with the given condition, then the triangles are congruent but by SAS congruence criteria neither by ASA nor AAS congruence criterion.