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siniylev [52]
2 years ago
6

18 multiply by 902 - 6 + 521

Mathematics
1 answer:
trapecia [35]2 years ago
4 0

Answer:

16751

Step-by-step explanation:

please mark my answer in brainlist

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Eric found that about 60% of 80 classmates at school like hip-hop music. However, 70% of his 60 relatives like hip-hop.
DerKrebs [107]

Answer:

60% of 80 is about 48. 70% of 60 is 42. The number of his classmates who like hip-hop is greater than the number of his relatives who like hip-hop.

Step-by-step explanation:

6 0
3 years ago
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Y=0.5x find the slope and the y-intercept
Vladimir79 [104]
Y=mx+b
m= slope so slope= .5
b= y intercept so y intercept=0
3 0
3 years ago
Which number can be used as a common denominator for the fractions 1/4 and 5/6? Check all that apply.
Juli2301 [7.4K]
You could either use 12 or 24.
6 0
3 years ago
Give a rule of the piecewise-defined function.
nataly862011 [7]

The equation of the piecewise function is f(x) = \left[\begin{array}{ccc}3&x \le -1\\-1&x > 2\end{array}\right

<h3>The piecewise function</h3>

On the graph, we have:

  • y = 3 for all x values not more than -1
  • y = -1 for all values greater than 2

Hence, the piecewise function is:

f(x) = \left[\begin{array}{ccc}3&x \le -1\\-1&x > 2\end{array}\right

<h3>The domain of the function</h3>

This is the set of input values

In (a), we have:

x ≤ -1 and x > 2

Hence, the domain is (∞, 3] u (2, ∞)

<h3>The range of the function</h3>

This is the set of output values

In (a), we have:

f(x) = 3 and f(x) -1

Hence, the range is [3] u (-1)

Read more about piecewise function at:

brainly.com/question/18859540

#SPJ1

5 0
1 year ago
There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0
3 years ago
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