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V125BC [204]
3 years ago
15

HELPP ME!!! What is f(3)?

Mathematics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:

\huge\boxed{\sf f(3)=20}

Step-by-step explanation:

<u>Given function is:</u>

f(x) =3x^2-4x+5

Put x = 3

f(3) =3(3)^2-4(3)+5\\\\f(3)=3(9)-12+5\\\\f(3)=27-12+5\\\\f(3)=15+5\\\\f(3)=20\\\\\rule[225]{225}{2}

mina [271]3 years ago
6 0

Answer:

3(3)^2- 4(3) + 5 = 20

Step-by-step explanation:

f(x) just means function so you plug in the value of x in the equation and solve.

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Clear selection<br>11. The mean of 2,5, (x+1),(x+2), 7 and 9 1 point<br>is 6. Find the median.​
nadezda [96]

Answer:

median= 6.5

Step-by-step explanation:

6= 2+5+x+1+x+2+7+9/6

summing up the values

26+2x=36

collecting like terms,

2x=10

divide both sides by 2

x= 5

5+1=6

5+2=7

so the numbers are 2 5 6 7 7 and 9

the median = 6+7/2

= 6.5

4 0
3 years ago
The length of a rectangle is 18 centimeters less than five times its width. its area is 35 square centimeters. find the dimensio
Studentka2010 [4]
35 = 5*7
7 = 5*5 -18

The dimensions of the rectangle are: length = 7 cm, width = 5 cm.

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It is handy to know your times tables.

___
If you want, you can write a couple of equations and solve them.
.. L = 5W -18
.. LW = 35
Substituting for L, we have
.. (5W -18)W = 35
.. 5W^2 -18W -35 = 0 . . . . put in standard form
.. (W -5)*(5W +7) = 0 . . . . . factor
.. W = 5 or -7/5 . . . . . . . . . we are only interested in the positive solution

The width of the rectangle is 5 cm; its length is 7 cm.
5 0
3 years ago
DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . DG=5 centimeters and BD=12 centimeters. What
pshichka [43]
Your answer should be 13cm
4 0
3 years ago
Read 2 more answers
A box of volume 180 m3 with square bottom and no top is constructed out of two different materials. The cost of the bottom is $4
zysi [14]

Answer:

Side of square bottom=6.46 m

Height of box=4.31 m

Step-by-step explanation:

Let s be the side bottom

Height of box=h

Volume of box=180m^3

Volume of box=lbh=s^2h

s^2h=180

h=\frac{180}{s^2}

Cost of bottom=$40 per square  m

Cost of sides =$30 per square  m

Total cost=C=40s^2+30(4sh)

C=40s^2+120s\times \frac{180}{s^2}

C(s)=40s^2+\frac{21600}{s}

Differentiate w.r.t s

C'(s)=80s-\frac{21600}{s^2}

C'(s)=0

80s-\frac{21600}{s^2}=0

80s=\frac{21600}{s^2}

s^3=\frac{21600}{80}=270

s=(270)^{\frac{1}{3}}=6.46

Again,differentiate w.r.t s

C''(s)=80+\frac{43200}{s^3}

Substitute s=6.46

C''(6.46)=80+\frac{43200}{(6.46)^3}=240.2>0

Hence, the cost is minimum at s=6.46

h=\frac{180}{s^2}=\frac{180}{(6.46)^2}=4.31

Side of square bottom=6.46 m

Height of box=4.31 m

5 0
3 years ago
An animal rescue group tracks how their marketing impacts the pet adoptions that occur each year. A record of adoptions for a 12
jenyasd209 [6]

Answer:

Step-by-step explanation:

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8 0
2 years ago
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