For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
Answer:
5.25
Step-by-step explanation:
15/10=1.5
9*1.5=13.5
13.5-3=10.5
10.5/2=5.25
To determine which of the choices is lies on the line represented by the equation, 2x + 5y = 4, substitute the values of the abscissas to the x of the equation and solve for y. Evaluate if the y calculated is equal to the ordinate of the ordered pair. Calculations are shown below.
A. (7, -2) ; 2(7) + 5y = 4 ; y = -2 ; EQUAL
B. (0,-1) ; 2(0) + 5y = 4 ; y = 0.8 ; NOT EQUAL
C. (0,1) ; 2(0) + 5y = 4 ; y = 0.8 ; NOT EQUAL
D. (3, -2) ; 2(-3) + 5y = 4 ; y = 2 ; NOT EQUAL
Thus, the answer is letter A. (7, -2)
The probability of an event is considered fair when the probability of the event happening is equally likely.
Thus, the way <span>each vote should be counted so that the outcome is fair is "</span><span>The freshman votes count as 1 vote, the sophomore as 1.14 votes, the juniors as 1.45 votes, and the seniors as 1.23 votes.</span>"
