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Zolol [24]
3 years ago
5

Please Help! Question is:

Mathematics
2 answers:
ki77a [65]3 years ago
8 0

Answer:

D - There is likely an association because 0.8 is not similar to 0.33.

Step-by-step explanation:

Got it right on ed. Hope this helps!

Natasha_Volkova [10]3 years ago
5 0

Answer: D

Step-by-step explanation:

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Please answer: <br> p - 4 = -9 + p
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Step-by-step explanation:

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Write the equation of the circle graphed below
Norma-Jean [14]

Answer:

The equation of the circle is

(x + 2)² + (y + 2)² = 9

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Step-by-step explanation:

The general equation of a circle is given as

(x - h)² + (y - k)² = r²

Where (h, k) is the center of the circle, and r is the radius.

Looking at the graph, the center is the red dot. It corresponds to -2 on the y-axis, and -2 on the x-axis. So, the center (h, k) is (-2, -2).

The radius is the distance from the center of the circle to the edge of the circle. The red dot is the edge of the circle, there are 3 lines that represent 3 units, so we have a radius of 3 units.

Using these in the general equation, we have

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And this is the equation.

6 0
3 years ago
A company receives shipments of a component used in the manufacture of a component for a high-end acoustic speaker system. When
Tanya [424]

Answer:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

Step-by-step explanation:

For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.

We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:

\hat p = \frac{24}{250}= 0.096

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.33  

And the margin of error would be:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

4 0
3 years ago
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