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Neko [114]
2 years ago
15

PLEASE HELP!! I DO NOT UNDERSTAND THIS ONE BIT. PLEASE RESPOND!

Mathematics
1 answer:
Slav-nsk [51]2 years ago
4 0
Substitute z with 3.
3(4)^3
Cube 4 with 3
3(64)
Multiply 3 and 64
=192
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What is the formula for the following arithmetic sequence? 12, 6, 0, -6, ...
bixtya [17]

Answer:

an= 12 + (-6)(n-1)

Step-by-step explanation:

you should find two values: a1 and d

a1= first number =12

d= a number of the sequence mines the number of the sequence before the one you chose = 0-6 = -6

a1+(n-1)d= 12-6(n-1)

6 0
3 years ago
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You owe your mom 10$. You pay her back 7$. Write an expression that can be used to represent this situation.
mezya [45]

Answer:

10$-7$=3$

Step-by-step explanation:

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Help please, I don't know how to answer....
Alchen [17]

Step-by-step explanation:

the last one

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2 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
2 years ago
How do you find the value of X​
deff fn [24]

Answer:

look at the angles. they all ad up to 180 degrees devide that by 9, and there you go!

Step-by-step explanation:

7 0
3 years ago
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