2 years ago

Question 3 of 10

Mathematics

1 answer:

nlexa [21]2 years ago

5 0

Step-by-step explanation:

$therefore \: x = 1$

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How many milliliters of normal saline are needed to have a concentration of 0.3 mg per ML for 150 mg dose of Etoposide?

Mamont248 [21]

Answer:

500 millilitres

Step-by-step explanation:

Mass = Concentration x Volume

This rearranged gives:

Volume = Mass / Concentration

= 150 / 0.3 = 500 millilitres

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3 years ago

6,975,000,000=5(3)^x<br> (this is an exponential equation)

zhenek [66]

X= log1395000000
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Log 3

In decimal form: 19.166143

8 0

3 years ago

Please help do not understand

Travka [436]

I think 5 is d n 6 is ac

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3 years ago

Read 2 more answers

6a-5b=9 2a+5b=23 using the addition method

rodikova [14]

Answer:

a = 4

b = 3

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4 0

3 years ago

Let f(x) = x^2 + 6x.

rusak2 [61]

Answer:

(A) The slope of secant line is 18.

(B) The slope of secant line is h+16.

Step-by-step explanation:

(A)

The given function is

$f(x)=x^2+6x$

At x=3,

$f(3)=(3)^2+6(3)=27$

At x=9,

$f(9)=(9)^2+6(9)=135$

The secant line joining (3,27) and (9,135). So, the slope of secant line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{135-27}{9-3}=18$

The slope of secant line is 18.

(B)

The given function is

$f(x)=x^2+6x$

At x=5,

$f(5)=(5)^2+6(5)=55$

At x=5+h,

$f(5+h)=(5+h)^2+6(5+h)=h^2 + 16 h + 55$

The secant line joining (5,55) and $(5+h,h^2 + 16 h + 55)$ . So, the slope of secant line is

$m=\dfrac{h^2 + 16 h + 55-55}{5+h-5}$

$m=\dfrac{h^2 + 16 h }{h}$

$m=h+16$

The slope of secant line is h+16.

4 0

4 years ago