The coordinate points that are on the line are (4, 11), (6, 14), and (30 50)
<h2>Equation of a line</h2>
The equation of a line in slope-intercept form is expressed as y = mx + b
Given the coordinate points (0, 5) and (2, 8), first, we need to find the equation of the line passing through this point.
<h3>Slope and intercept of a line</h3>
<u>Get the slope of the equation:</u>

The y-intercept is the point where x = 0. From the given coordinates, you can see that b = 5.
<u>Get the required equation:</u>
Recall that y = mx + b. On substituting;
y = 1.5x + 5
Next is to check which of the points listed are on the line.
<u>For the coordinate (4,11).</u>
If x = 4
y = 1.5(4) + 5
y = 6 + 5
y = 11
Therefore (4, 11) is on the line y = 1.5x + 5
<u>For the coordinate (5,10).</u>
If x = 5
y = 1.5(5) + 5
y = 7.5 + 5
y = 12.5
Therefore (5, 10) is NOT on the line y = 1.5x + 5
<u>For the coordinate (6,14).</u>
If x = 4
y = 1.5(6) + 5
y = 9 + 5
y = 14
Therefore (6, 14) is on the line y = 1.5x + 5
<u>For the coordinate (30,50).</u>
If x = 30
y = 1.5(30) + 5
y = 45 + 5
y = 50
Therefore (30, 50) is on the line y = 1.5x + 5
<u>For the coordinate (40,60).</u>
If x = 40
y = 1.5(40) + 5
y = 60 + 5
y = 65
Therefore (40, 65) is on NOT the line y = 1.5x + 5
Hence the coordinate points that are on the line are (4, 11), (6, 14), and (30 50).
Learn more on the equation of a line here: brainly.com/question/13763238