Answer:
The area of △AON and the area of △ABC is x. The area of △AON is one-sixth part of △ABC.
Step-by-step explanation:
Let the total area of △ABC be x.
A median of a triangle divides the area of a triangle in two equal parts.
Since AM are CN are medians, therefore the area of △ACN, △BCN, △ABM and △ATM are equal, i.e., .
A centroid is the intersection point of all medians of a triangle. A centroid divides each median in 2:1.
Since CN is median and O is the centroid of the triangle, therefore CO:ON is 2:1.
Draw a perpendicular on CN from A as shown in below figure. Let the height of the pendicular on CN from A be h.
Therefore the area of △AON is one-third of △ACN.
The area of ANO is . Therefore the area of △AON is one-sixth part of △ABC.
Answer:
That would be 84.
Step-by-step explanation:
Here it is
Answer: the areas of irregular shapes can be find by calculating the areas. To find area of a figure which is a combination of rectangles and a squares, you have to calculate the area of each figure separately and then add them to find total area.
Step-by-step explanation:
Two Consecutive Odd Numbers: D, D+2
(D+2) + 2D = 4D - 27
D + 2 + 2D = 4D - 27
3D + 2 = 4D - 27
3D + 29 = 4D
29 = D
Two Consecutive Odd Numbers are 29, 31
Check. . 31 + 2(29) = 4(29) - 27
..................31 + 58 = 116 - 27
.................89 = 89 ..... CORRECT!
Answer:
AB = 15
A = 53º
B = 37º
Step-by-step explanation:
To find AB you can use pythagoream's theorem.
To find the angle A, use sine
To find B, remember that all of the angles of a triangle add up to 180º. If you already have 90º + 53º + x =180º
143º+x=180º
Subtract 143
x=180º-143º
x=37º