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Over [174]
2 years ago
15

The weakest gravitational force caused by the Moon is called the __________, which is found at the point on Earth farthest from

the Moon.
Physics
1 answer:
skad [1K]2 years ago
4 0
This is called Nadir.
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Ken’s community is completely dependent on agriculture for their income. They cultivate and breed domestic species for their foo
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<span>This is an agrarian society, taken to its extreme. These societies are largely dependent upon farming and related activities as a way of earning income, and also for using the farmed items as a way of supporting oneself as food and clothing.</span>
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3 years ago
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Cuales son las diferencias entre el helio y el hidrógeno?
allsm [11]

El helio es más ligero que el aire y a diferencia del hidrógeno no es inflamable, siendo además su poder ascensional un 8 % menor que el de este, por lo que se emplea como gas de relleno en globos y zepelines publicitarios, de investigación atmosférica e incluso para realizar reconocimientos militares.espero ke esto ayude!

7 0
3 years ago
A 25.0-gram bullet enters a 2.25-kg watermelon with a speed of 220 m/s and exits the opposite side with a speed of 110 m/s. If t
umka21 [38]

Answer:

3.67 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

mu+m'u' = mv+m'v'............................... Equation 1

Where m = mass of the bullet, m' = mass of the watermelon, u = initial velocity of the bullet, u' = initial velocity of the watermelon, v =  final velocity of the bullet, v' = final velocity of the watermelon.

make v' the subject of the equation,

v' = (mu+m'u'-mv)/m'....................... Equation 2

Given: m = 25 g = 0.025 kg, u = 220 m/s, m' = 2.25 kg, u' = 0 m/s ( at rest), v = 110 m/s.

Substitute into equation 2

v' =[ (0.025×220) +(2.25×0)+(0.025×110)]/2.25

v' = 3.67 m/s.

Hence the velocity of the watermelon = 3.67 m/s

7 0
4 years ago
The Bernoulli principle states that the pressure inside a liquid increases with depth:
Vera_Pavlovna [14]
<h2>Answer: B. False</h2>

Explanation:

According to Bernoulli's principle:

<em>"In an ideal fluid (not viscous and without friction) that circulates through a closed conduit, the energy the fluid possesses remains constant along its path." </em>

From there, Bernoulli deduced that the fluid pressure decreases when the flow rate increases. <u>And this has nothing to do with depth. </u>

<u> </u>

To understand it better:

In a fluid that circulates through a closed conduit (a pipe for example), it contains energy in two ways:

-Kinetic energy due to its <u>weigh</u>t and <u>speed. </u>

-Potential energy in the form of <u>pressure. </u>

Now, if the system has constant flow and the total energy (kinetic + potential) is also constant, <u>the energy is transformed every time the transverse area of ​​the tube is modified. </u>

It should be noted that by modifying this transverse area, the flow rate is also modified.

Therefore, <u>as the kinetic energy increases or decreases, this change is compensated by the decrease or increase in pressure</u> (potential energy), since the total energy of the system cannot be created or destroyed.

7 0
3 years ago
A body of mass 400 g is moving along a smooth surface at a velocity of 10 m s–1 east. It strikes a body of mass 650 g, initially
9966 [12]

Answer: v = 2.53 m/s at E 53.1° S

Explanation:

Conservation of momentum

The 400 g object has no North-South velocity, so the initial momentum in that direction is zero. The total momentum after collision must also be zero

0 = 400(8sin35) + 650vy

vy = -2.82376... m/s

In the East direction

400(10) = 400(8cos35) + 650vx

vx = 2.121097...m/s

v = √(2.12² + 2.82²) = 3.531667... ≈ 2.53 m/s

θ = arctan(vy/vx) = arctan(-2.82/2.12) = -53.087... ≈ E53.1°S

4 0
3 years ago
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