Ask question

Ask question

All categories

Novosadov [1.4K]

3 years ago

10

If you want a charged object to become neutral,then you have to ————-? A.Touch it with a positively charged object B.Touch it wi

th neutral objects C.Touch it with a negativity charged object D.Touch it with the ground

2 answers:

JulsSmile [24]3 years ago

6 0

A) Touch it with a positively charged object

OlgaM077 [116]3 years ago

3 0

Answer: D.Touch it with the ground

Explanation:

The charged object can become neutral if touched with the ground in a process known as grounding.

If the charged object is negatively charged, excess electrons will flow into the ground thus making the object neutral. If the object is positively charged, electrons will flow from the ground into the object and neutralise it.

You might be interested in

Helppppppp its exam

UkoKoshka [18]

Answer:

a. 240.2 C

Explanation:

7 0

3 years ago

Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.7

Sophie [7]

Answer:

B) 1.2 N, toward the center of the circle

Explanation:

The circumference of the circle is:

C = 2πr

C = 2π (0.70 m)

C = 4.40 m

So the velocity of the ball is:

v = C/t

v = 4.40 m / 0.60 s

v = 7.33 m/s

Sum of the forces in the radial direction:

∑F = ma

T = m v² / r

T = (0.015 kg) (7.33 m/s)² / (0.70 m)

T = 1.2 N

The tension force is 1.2 N towards the center of the circle.

4 0

3 years ago

Read 2 more answers

If bullets are fired from an airplane in the forward direction of its motion, the momentum of the airplane will be:_______

lorasvet [3.4K]

Answer:

I Dont know sorry.........

8 0

3 years ago

Joe is measuring the time it takes for a ball to roll down a ramp. In this experiment Joe takes the measurement 5 times and gets

PolarNik [594]

Step by step solution :

standard deviation is given by :

$\sigma = \sqrt\dfrac{{\sum (x-\bar{x})^2}}{n}$

where, $\sigma$ is standard deviation

$\bar{x}$ is mean of given data

n is number of observations

From the above data, $\bar{x}=24.88$

Now, if $x=24.8$ , then $(x-\bar{x})^2=0.0064$

If $x=23.9$ , then $(x-\bar{x})^2=0.9604$

if $x=26.1$ , then $(x-\bar{x})^2=1.4884$

If $x=25.1$ , then $(x-\bar{x})^2=0.0484$

If $x=24.5$ , then $(x-\bar{x})^2=0.1444$

so, $\sum (x-\bar{x})^2 =\frac{0.0064+0.9604+1.4884+0.0484+0.1444}{5}$

$\sum (x-\bar{x})^2 =2.648$

$\sqrt{\sum \frac{(x-\bar{x})^2}{n}}$

$\sigma =0.7277$

No, Joe's value does not agree with the accepted value of 25.9 seconds. This shows a lots of errors.

6 0

3 years ago

A cue ball has a mass of 0.5 kg. During a game of pool, the cue ball is struck and now has a velocity of 3 . When it strikes a s

photoshop1234 [79]

Answer: 3 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum: during the collision between the two balls, the total momentum of the system before the collision and after the collision must be conserved:

$p_i = p_f$

The total momentum before the collision is given only by the cue ball, since the solid ball is initially at rest, therefore

$p_i = m_c u_c = (0.5 kg)(3 m/s)=1.5 kg m/s$

So, the final total momentum will also be

$p_f = 1.5 kg m/s$

And the total momentum after the collision is given only by the solid ball, since the cue ball is now at rest, therefore:

$p_f = m_s v_s$

from which we find the velocity of the solid ball

$v_s = \frac{p_f}{m_s}=\frac{1.5 kg m/s}{0.5 kg}=3 m/s$

8 0

3 years ago

Read 2 more answers