Answer:
PE= m * g *h
work:
PE= 65kg * 9.8 kg *8,800 m
PE=5605600 m/kg
idk the actual units i forgot
Answer:
When the ball goes to first base it will be 4.23 m high.
Explanation:
Horizontal velocity = 30 cos17.3 = 28.64 m/s
Horizontal displacement = 40.5 m
Time
Time to reach the goal posts 40.5 m away = 1.41 seconds
Vertical velocity = 30 sin17.3 = 8.92 m/s
Time to reach the goal posts 40.5 m away = 1.41 seconds
Acceleration = -9.81m/s²
Substituting in s = ut + 0.5at²
s = 8.92 x 1.41 - 0.5 x 9.81 x 1.41²= 2.83 m
Height of throw = 1.4 m
Height traveled by ball = 2.83 m
Total height = 2.83 + 1.4 = 4.23 m
When the ball goes to first base it will be 4.23 m high.
Radiometric dating?
Also, possibly radiocarbon dating
The position of the first ball is

while the position of the second ball, thrown with initial velocity
, is

The time it takes for the first ball to reach the halfway point satisfies



We want the second ball to reach the same height at the same time, so that




Well,
A = T or U
C = G
G = C
T or U = A
So it would be like this;
DNA Sequence: GCTAATTGCATCCGA
The Complementary Sequence: CGATTAACGTAGGCT
Hope this helped :)