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3 years ago

What would happen to the moon if earth stopped exerting the force of gravity on it?

2 answers:

6 0

There are two equal forces of gravity between the Earth and the Moon.
One force pulls the Moon toward the Earth.
The other force pulls the Earth toward the Moon.

If only this gravity suddenly switched off, then the moon would
continue to orbit the Sun, very much as it does now.

If ALL gravity suddenly switched off, then . . .

-- the Moon would stop orbiting the Earth and would sail away, in
a straight line and at the speed it had when gravity disappeared;

-- the Earth would stop orbiting the Sun and would sail away, in
a straight line and at the speed it had when gravity disappeared;

-- all the gases surrounding the Earth ... which we call "air" ... would
start drifting away, and expanding into a giant cloud of gas, and stop
being an atmosphere;

-- the Sun would completely fall apart, expand into a giant cloud of gas,
and stop being a star.

larisa86 [58]3 years ago

3 0

The moon will stop orbiting and will fly away and never stop running

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Two iron weights, one twice the mass of the other, are dropped from the top of a building. Compared with the lighter weight, the

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The twice as heavy weight will hit the ground with more force, or impact.

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2 years ago

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What role does actin and myosin play in the process of muscle contraction?

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1 year ago

A bullet is fired into the air at an angle of 30° to the horizontal. At the same time and from the same height,

enyata [817]

Answer:

The bullet that is fired will spend longer in the air, hitting the ground after the dropped bullet.

Explanation:

Using the equation: x = x 0 + v t

If we neglect the effects of air resistance, the horizontal motion is a constant velocity.

The horizontal displacement = (velocity X cosθ)

So, the fired bullet has to travel horizontally before falling which takes a longer time compared to a bullet dropped where it is, height = 1/2 gt^2

gravity, g = 9.8 m/s2.

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2 years ago

One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separat

marin [14]

Answer:

B. 2.77 x $10^{-4}$ N

Explanation:

The required force can be calculated by:

F = $\frac{Kq_{1}q_{2} }{d^{2} }$

Where F is the force between the particles, K is the coulomb's constant (9 x $10^{9}$ $Nm^{2}/C^{2}$ ), $q_{1}$ is the charge on the first particle, $q_{2}$ is the charge on the second particle and $d^{2}$ is the distance between the particles.

So that:

F = $\frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9} }{(0.015)^{2} }$

= $\frac{6.2307*10^{-8} }{(2.25*10^{-4} }$

= 2.7692 x $10^{-4}$

The force between the particles is 2.77 x $10^{-4}$ N.

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2 years ago

You are using an 8 th order low-pass filter. Determine the roll-off achievable in the stop band, in dB/dec, and determine the ph

Andreas93 [3]

Answer: The complexity of filter is the order of the filter. Greater the order of the filter, more efficient the filter is. Roll of value of one filter is 20dB/dec. So the roll-off value of 8th order filter is 160dB/dec. 8th order filter is more efficient than the second order low-pass filter.

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3 years ago