Question

PLEASE HELP A student climbs to the top of a press box where the cameras are. He wonders how many meters he is off of the ground below. So he drops a golfball he had in his pocket, and his friend times how long it takes for the ball to hit the concrete behind the press box. If it takes 1.5 seconds for the ball to hit. What is the height of the rail on top of the press box where the ball was dropped from?

Answer 1

The height of the rail on top of the press box where the ball was dropped from is 11.025 m.

The given parameters:

• Time of motion of the ball, t = 1.5 s
• Let the height of the rail = h

Maximum height of fall;

• The maximum height through which the ball was dropped from is calculated by applying second equation of motion;

$h = v_0_y t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = \frac{1}{2} (9.8) (1.5)^2\\\\h = 11.025 \ m$

Thus, the height of the rail on top of the press box where the ball was dropped from is 11.025 m.

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