Match the expression to the method needed to evaluate (will give brainlest)
2 answers:
Answer:
See image
Step-by-step explanation:
This is to help you practice exponent rules. The rules are short cuts, which are good bc they're faster but bad bc they take away the meaning of the work. If you're trying to remember a rule, think through the meaning. See image.
So, "multiply exponents" and "product of powers" are basic two equivalent phrases! I think the answers on the image should work, but jic if not switch those two.
The Add exponents rule and Subtract are 100% correct.
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Answer:
a) 91.33% probability that at most 6 will come to a complete stop
b) 10.91% probability that exactly 6 will come to a complete stop.
c) 19.58% probability that at least 6 will come to a complete stop
d) 4 of the next 20 drivers do you expect to come to a complete stop
Step-by-step explanation:
For each driver, there are only two possible outcomes. Either they will come to a complete stop, or they will not. The probability of a driver coming to a complete stop is independent of other drivers. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.
This means that
20 drivers
This means that
a. at most 6 will come to a complete stop?
In which
91.33% probability that at most 6 will come to a complete stop
b. Exactly 6 will come to a complete stop?
10.91% probability that exactly 6 will come to a complete stop.
c. At least 6 will come to a complete stop?
Either less than 6 will come to a complete stop, or at least 6 will. The sum of the probabilities of these events is decimal 1. So
We want . So
In which
19.58% probability that at least 6 will come to a complete stop
d. How many of the next 20 drivers do you expect to come to a complete stop?
The expected value of the binomial distribution is
4 of the next 20 drivers do you expect to come to a complete stop