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2 years ago

Evaluate the expression please.

Mathematics

1 answer:

Tanzania [10]2 years ago

6 0

Answer:

-7

Step-by-step explanation:

-3-(-10)/-2+1

-3-5+1

-8+1

-7

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Kurt needs pounds of chocolate chips to make cookies. How many ounces of chocolate chips does he need? PLEASE I NEED IT RIGHT AW

Bad White [126]

Answer:

Step-by-step explanation:

Multiply the number of pounds by 16.

1 LB=16OZ

16x(lbs)= ANSWER

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3 years ago

HELP!!! Need to find the Area (Pic)

PtichkaEL [24]

Answer: 173.82cm^2

Step-by-step explanation:

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2 years ago

Each sector shown has an equal area.

valentina_108 [34]

Answer:

I think it is 40% (Not sure)

Step-by-step explanation:

First, you want to find out how much percent is in one square. To find that out you divide 5 by 100 because 100 is basically 1 in this situation. 100/5 is equal to 20% so that means any one part (Shaded or not) is 20%. Then add the shaded squared up and you get 40%.

7 0

3 years ago

Easier way to learn multiplication

joja [24]

Do this every day
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6 0

3 years ago

To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine foun

QveST [7]

Answer:

We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 31.7 milligrams

Sample mean, $\bar{x}$ = 28.5 milligrams

Sample size, n = 9

Alpha, α = 0.05

Sample standard deviation, s = 2.8 milligrams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 31.7\text{ milligrams}\\H_A: \mu < 31.7\text{ milligrams}$

We use One-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{28.5 - 31.7}{\frac{2.8}{\sqrt{9}} } = -3.429$

Now, $t_{critical} \text{ at 0.05 level of significance, 8 degree of freedom } = -1.860$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

3 0

3 years ago