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Zinaida [17]
4 years ago
15

Arestaurant wishes to have at least one server for every 12 tables. Each of the tables in the restaurant seats four guests. If x

s the number of servers and y is the number of guests, which inequality represents the restaurant's desired relationship of the number of servers to the number of guests?
Mathematics
2 answers:
frozen [14]4 years ago
8 0
That is the wrong answer everyone
Crazy boy [7]4 years ago
7 0

Answer:

48x\geq y

Step-by-step explanation:

Given that a restaurant wishes to have at least one server for every 12 tables. Each of the tables in the restaurant seats four guests. If x s the number of servers and y is the number of guests,

Since number of servers should be atleast for every 12 tables we can write this as number of servers should be at least 1 for every 48 guests

So correct inequality would be

x\geq \frac{y}{48} \\48x\geq y

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Shkiper50 [21]
Get x by itself
add 16 to both sides, so 4x = 16
divide both side by 4 and x =4
4 0
2 years ago
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Alex73 [517]

Answer:

It was ordinary

Step-by-step explanation:

7 0
3 years ago
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Pleaseeeee help!!!!!<br> Order them least to greatest please
Fiesta28 [93]

Answer and Step-by-step explanation:

\pi is pi, or 3.14159

The absolute value of -4 ( |-4| ) is 4.

These numbers should go in this order:

-10   <   0.121212...   <   \pi   <   |-4|   <   5\frac{1}{2}

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8 0
3 years ago
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Y&lt;=x-5, and y&lt;=-x-4 would be points (1,10)? or<br> (-1,10)<br> (10,1)<br> 1,-10)
weeeeeb [17]
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4 0
3 years ago
Help,anyone can help me do quetion.​
3241004551 [841]

Answer:

(a) x = 128^{o}

(b) x = 74^{o}

Step-by-step explanation:

A. sum of angles in a polygon = (n - 2) 180

The polygon given is an irregular pentagon, where n = 5

So that;

sum of angles in a pentagon = (5 - 2) 180

                        = 3 x 180

                        = 540^{o}

Thus,

x + 90 + 76 + 110 + 136 = 540^{o}

x + 412 = 540^{o}

x = 540^{o} - 412

x = 128^{o}

B. The polygon given is an irregular pentagon, where n = 5.

Let the supplementary angle with angle 38 be represented by y,

y + 38 = 180

y = 180 - 38

  = 142^{o}

y = 142^{o}

Let the supplementary angle with x be represented by z, so that;

z + 72 + 120 + 100 + 142 = 540^{o}

z + 434 = 540^{o}

z = 540^{o} - 434

  = 106^{o}

z = 106^{o}

But, x + z = 180^{o}

Then;

x + 106^{o} = 180^{o}

x = 180^{o} - 106^{o}

  = 74^{o}

x = 74^{o}

7 0
3 years ago
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