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2 years ago

What value of y satisfies the system of equations below? 2x - y = 6 2x + 3y = 14

Mathematics

1 answer:

Oksana_A [137]2 years ago

5 0

Answer: y=2

Step-by-step explanation:

2x+3y=14 - 2x-y=6 = 4y=8

y=2

If you need x, just insert y into the equation and work out x from there

2x-2=6

2x=8

x=4

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What is 34% written as a ratio?<br> A) 34:1 <br> B) 34:10 <br> C) 34:100 <br> D) 34:1000

VikaD [51]

34%/100=0.34 and that is equal to 34:100 aka 34/100.

Hoped I helped!

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2 years ago

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3 years ago

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station. Find the ra

Anika [276]

Answer:

The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

Step-by-step explanation:

Given information:

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.

$z=1$

$\frac{dx}{dt}=430$

We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

$y=2$

According to Pythagoras

$hypotenuse^2=base^2+perpendicular^2$

$y^2=x^2+1^2$

$y^2=x^2+1$ .... (1)

Put z=1 and y=2, to find the value of x.

$2^2=x^2+1^2$

$4=x^2+1$

$4-1=x^2$

$3=x^2$

Taking square root both sides.

$\sqrt{3}=x$

Differentiate equation (1) with respect to t.

$2y\frac{dy}{dt}=2x\frac{dx}{dt}+0$

Divide both sides by 2.

$y\frac{dy}{dt}=x\frac{dx}{dt}$

Put $x=\sqrt{3}$ , y=2, $\frac{dx}{dt}=430$ in the above equation.

$2\frac{dy}{dt}=\sqrt{3}(430)$

Divide both sides by 2.

$\frac{dy}{dt}=\frac{\sqrt{3}(430)}{2}$

$\frac{dy}{dt}=372.390923627$

$\frac{dy}{dt}\approx 372$

Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

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3 years ago

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I really need help with this

ValentinkaMS [17]

Answer:

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Step-by-step explanation:

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