We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
I’m pretty sure it is 57?
Answer:
18/25, 5/4, 1.3
Step-by-step explanation:
What you need to do is to divide each fraction so that you can change to a number.
18÷25=0.72
5÷4=1.25
Answer:
1. 32, 12
2. Enlargement
Step-by-step explanation:
Enlarged by a scale factor of 4
(Multiply all points by 4)
8 x 4 = 32
3 x 4 = 12
It is an enlargement because the points are larger than before.
Answer:
<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>0</u></em></h2>
Step-by-step explanation:
8(2 + x) = 3x + 16 + 5x
=> 16 + 8x = 3x + 16 + 5x
=> 8x - 3x - 5x = 16 - 16
=> 0x = 0
=> <em><u>x = 0 (Ans)</u></em>
