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3 years ago

H(x=-10x+6 find h(0)

Mathematics

2 answers:

DerKrebs [107]3 years ago

6 0

Answer:

Step-by-step explanation:

H(x)=-10x+6

H(0) means x=0

Hence

H(0)=-10(0)+6

H(0)=0+6

H(0)=6

gtnhenbr [62]3 years ago

3 0

Answer:

h(0) = 6

Step-by-step explanation:

Plug x = 0 to find h(0)

h(0) = -10.0 + 6 = 6

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3 years ago

The function f is defined by f(x)=2.1x−1.7. Use this formula to find the following values of f.

viktelen [127]

f(c + a) = 2.1 c + 2.1 a - 1.7

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Step-by-step explanation:

The function is f(x) = 2.1 x - 1.7

We need to use this formula to find

f(c + a)
f(1/3x - 2/3)
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To solve the problem substitute x by each value in the bracket

∵ f(x) = 2.1 x - 1.7

f(c + a) means substitute x by c + a

∵ x = c + a

∴ f(c + a) = 2.1(c + a) - 1.7

- Multiply the bracket by 2.1

∴ f(c + a) = 2.1 c + 2.1 a - 1.7

∵ f(x) = 2.1 x - 1.7

- f(1/3 x - 2/3) means substitute x by 1/3 x - 2/3

∵ x = 1/3 x - 2/3

∴ f(1/3 x - 2/3) = 2.1(1/3 x - 2/3) - 1.7

- Multiply the bracket by 2.1

∴ f(1/3 x - 2/3) = 0.7 x - 1.4 - 1.7

- Add the like terms

∴ f(1/3 x - 2/3) = 0.7 x - 3.1

∵ f(x) = 2.1 x - 1.7

- f(x + 2) means substitute x by x + 2

∵ x = x + 2

∴ f(x + 2) = 2.1(x + 2) - 1.7

- Multiply the bracket by 2.1

∴ f(x + 2) = 2.1 x + 4.2 - 1.7

- Add the like terms

∴ f(x + 2) = 2.1 x + 2.5

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- f(3c) means substitute x by 3c

∵ x = 3c

∴ f(3c) = 2.1(3c) - 1.7

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∴ f(3c) = 6.3 c - 1.7

Learn more:

You can learn more about the functions in brainly.com/question/628130

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3 0

3 years ago

$4000 is invested in a mutual fund that pays annual interest compounded quarterly for 15 years. What annual interest is needed t

Neporo4naja [7]

Answer:

The interest needed to reach that value of $6000 is 2.75%

Step-by-step explanation:

Given as :

The principal that invested in mutual fund = p = $4000

The time period = t = 15 years

The Amount after 15 years = A = $6000

Let The interest needed to reach that value = r%

Now, According to question

<u>From Compound Interest method</u>

Amount = principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, $6000 = $4000 × $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $\dfrac{6000}{4000}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

Or, $\frac{3}{2}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, 1.5 = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $1.5^{\frac{1}{15}}$ = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 - 1 = $\dfrac{r}{100}$

or, 0.0275 = $\dfrac{r}{100}$

∴ r = 0.0275 × 100

I.e r = 2.75

So, The interest needed to reach that value = r = 2.75%

Hence,The interest needed to reach that value of $6000 is 2.75% Answer

3 0

3 years ago