Let us assume that there is a 100g sample present. The respective mass of each element will then be:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Now, we divide each constituent's mass by its Mr to obtain the moles of each
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Dividing by the smallest number:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula is
C10H12NO
26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate. Explanation: Molar mass of compound = 120 g/mol.
The pressure (in atm) in a 5 L tank with 37.50 grams of oxygen gas at 350 K is 6.715 atm.
<h3>How do we calculate the pressure of gas?</h3>
Pressure of gas will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure = ?
V = volume = 5 L
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 350 K
n is the moles of gas and it will be calculated as:
n = W/M, where
W = given mass = 37.50 g
M = molar mass of oxygen = 32g/mol
n = 37.50/32 = 1.17 mol
On putting all these values, we get
P = (1.17)(0.082)(350) / (5) = 6.715 atm
Hence resultant pressure of the oxygen gas is 6.715 atm.
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Answer:
The protic solvents are (CH3)2CHOH, NH3, and HCONH2
The aprotic solvent are CH3NO2, CH2Cl2, and N(CH3)3
Explanation:
A protic solvent is a solvent that has a hydrogen atom bound to an oxygen (O), a nitrogen (N), or fluoride (F). Generally, any solvent that contains a labile H⁺ is called a protic solvent.
a. (CH3)2CHOH
(CH3)2CHOH is a protic solvent because one of the hydrogens is bound to oxygen (O)
b. CH3NO2
CH3NO2 is an aprotic (i.e not a protic solvent) solvent because all the hydrogens are bound to carbon.
c. CH2Cl2
CH2Cl2 is an aprotic solvent because all the hydrogens are bound to carbon.
d. NH3 is a protic solvent because all the hydrogens are bound to Nitrogen (N)
e. N(CH3)3 is an aprotic solvent because all the hydrogens are bound to carbon
f. HCONH2 is a protic solvent because two of the hydrogens are bound to Nitrogen (N)