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diamong [38]
4 years ago
13

What is the mass in 0.25 mol of SO2

Chemistry
1 answer:
gulaghasi [49]4 years ago
5 0

0.25 mols SO₂ x 64.058 g SO₂/ 1 mol SO₂ = 16.0145 g SO₂

molar mass of SO₂: 64.058 g

answer: 16 grams of SO₂ (2 sig figs)

check the question to see if its asked for a specific unit for mass (grams or kilograms, if they asked for kiligrams then convert 16 grams to kilograms by dividing it by 1000)


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The element Y has 13 electrons. What is the electronic configuration of
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Answer:

0,2,8,3

Explanation:

k shell takes 2,L shell takes 8 and M shell takes the remaining which is 3

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a swimming pool is 50 meters long. each day a swimmer swam total of 75 lengths of the pool for practice. how many kilometers did
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50x75=3750 -- metres per day
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A flask of volume 2.0 liters, provided with a stopcock, contains oxygen at 20 oC, 1.0 ATM (1.013X105 Pa). The system is heated t
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Answer:

1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).

2.6592 grams of oxygen remain in the flask.

Explanation:

Volume of the flask remains constant = V = 2.0 L

Initial pressure of the oxygen gas = P_1=1.0 atm

Initial temperature of the oxygen gas = T_1=20^oC =293.15 K

Final pressure of the oxygen gas = P_2=?

Final temperature of the oxygen gas = T_2=100^oC =373.15 K

Using Gay Lussac's law:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

P_2=\frac{P_1\times T_2}{T_1}=\frac{1 atm\times 373.15 K}{293.15 K}=1.27 atm

1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).

Moles of oxygen gas = n

P_1V_1=nRT_1 (ideal gas equation)

n=\frac{P_1V_1}{RT_1}=\frac{1 atm\times 2.0 L}{0.0821 atm l/mol K\times 293.15 K}=0.08310 mol

Mass of 0.08310 moles of oxygen gas:

0.08310 mol × 32 g/mol = 2.6592 g

2.6592 grams of oxygen remain in the flask.

6 0
3 years ago
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7 0
3 years ago
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