He made a mistake in step #2. It seemed to be a trivial mistake because it involved signs, but it still had a great impact. Since step#2, his solution was already wrong.
Instead of
(-1)²-4(2)(-6) = 1 + 48 = 49
What he did is
(-1)²-4(2)(-6) = -1 + 48 = 47
Answer:
4.It is continuous because the number of gallons can take on any value over a range of values.
Step-by-step explanation:
Discrete variables are ones that are disconnected. This means they take only specific values, with no values inbetween.
Continuous variables are ones that can take any value in a given range.
When measuring the gallons of gas, we can have partial gallons of gas; this means the variable can take any value in a given range, so it is continuous.
What should denise do for her next step?
Answer: Out of all the options presented above the one that best represents the next step that denise should take after already using her straightedge and compass to construct the circle, lines, and arcs is to use the straightedge to draw line ac, line ad, line bc, and line bd. use the compass and straightedge to construct the bisector of ∠cpb∠cpb. Please see the attachment as reference to how it should look like once it is completed.
I hope it helps, Regards.
Answer:
Rock D.
Step-by-step explanation:
We can assume that the force that the catapult does is always the same.
So, here we need to remember Newton's second law:
F = m*a
force equals mass times acceleration.
Where acceleration is the rate of change of the velocity.
So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.
So, we can rewrite:
a = F/m
So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.
Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.
So we can assume that rock D is the correct option.
49=16+x^2
x^2= 33
x= square root of 33
