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Leya [2.2K]
3 years ago
15

I

Mathematics
2 answers:
shtirl [24]3 years ago
8 0

a) 10 - 20 +45

Step-by-step explanation:

Is known :

She started with 10 points.

In the first round she lost 20 points.

In the second round she won 45 points.

Asked :

  • Which of the following shows the changes in Anayah scores?

Aswered :

She started with 10 points - In the first round she lost 20 points + In the second round she won 45 points

= 10 - 20 + 45

Elina [12.6K]3 years ago
5 0

Answer:

A.

Step-by-step explanation:

It's set up exactly as it is said. She starts with 10 points automatically so you would put:

10

Then it says that she lost 20 points. Losing is subtraction. You would add this to the equation:

10-20

Then it says she won 45 points. Winning is addition. You would add this to the equation:

10-20+45

This equation matches up with A. thus A. being the correct answer. If they ask for the answer, it is 35 by the way. Hope this helps!

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Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

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