First of all, we can observe that

So the expression becomes

This means that the expression is defined for every 
Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

Since we can't accept 3 as an answer, the actual solution set is
![(-\infty,-2] \cup [2,3) \cup (3,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-2%5D%20%5Ccup%20%5B2%2C3%29%20%5Ccup%20%283%2C%5Cinfty%29)
Answer:
5/6
Step-by-step explanation:
1/3 + 1/2
Must have matching denominators
1 1
----- + -------
3 (2) 2(3)
Whatever is done to the bottom (denominator) must be done to the top (numerator)
1(2) 1(3)
----- + -------
3 (2) 2(3)
2 3 5
----- + ------- = --------
6 6 6
Can I name Justin's sum as a single fraction: Yes
Would it be correct to name it 2/3: No. The fraction is equal to 5/6
I hope this helps!
Answer:
Step-by-step explanation:
Answer:
49
Step-by-step explanation: