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2 years ago

Which expression is not equivalent to -1.5(-6m+8n).

Mathematics

2 answers:

Evgen [1.6K]2 years ago

7 0

Answer:

Step-by-step explanation:

-1.5(-6m+8n) = 9m-12n

3(3m -4n) = 9m - 12n

9m -12n = 9m -12n

-6(-1.5m +2n) = 9m - 12n

-2(-4.5m+ 4n) = 9m - 8n

Mars2501 [29]2 years ago

3 0

Answer: D. -2(-4.5m + 4n)

Step-by-step explanation:

First, let us simplify -1.5(-6m+8n).

Given:

-1.5(-6m + 8n)

Distribute:

9m - 12n

[A] ✗

9 /3 = 3 and 12 / 3 = 4

This means that 3(3m - 4n) = 9m - 12n = -1.5(-6m+8n)

Option A is not our answer.

[B] ✗

Using this simplified version we did above, option B is not our answer as 9m - 12n = 9m - 12n and 9m - 12n = -1.5(-6m+8n).

[C] ✗

We will distribute option C to see if we reach the same expression. Seeing below, we do, so option C is not our answer.

-6(-1.5m + 2n)

9m - 12n

[D] ✓

Since none of the other options are correct, the answer to your question D because it is not equivalent.

Answer:

D. -2(-4.5m + 4n)

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A drawer contains 6 black neckties, 2 white neckties,4 red neckties,2 maroon neckties and 2 blue neckties. One necktie is picked

kogti [31]

A) The probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) The probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) The probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E ) the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

Step-by-step explanation:

Here, the total number of black neckties = 6

The total number of white neckties = 2

The total number of red neckties = 4

The total number of maroon neckties = 2

The total number of blue neckties = 2

The number of times the experiment is repeated = 300

A ) P(Picking a white tie) = $\frac{\textrm{Total number of white ties}}{\textrm{Total Bow ties}}$

= $\frac{2}{16} = \frac{1}{8}$

So, the probability of picking a white ONCE is 1/8.

Now, as the experiment is REPEATED 300 times with replacement.

So, the probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) P(Picking a BLUE tie) = $\frac{\textrm{Total number of blue ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a blue ONCE is 1/8.

Hence, the probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) P(Picking a Red tie) = $\frac{\textrm{Total number of Red ties}}{\textrm{Total Bow ties}} = \frac{4}{16} = \frac{1}{4}$

So, the probability of picking a red ONCE is 1/4.

Hence, the probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) P(Picking a Black tie) = $\frac{\textrm{Total number of black ties}}{\textrm{Total Bow ties}} = \frac{6}{16} = \frac{3}{8}$

So, the probability of picking a red ONCE is 3/8.

Hence, the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E) P(Picking a maroon tie) = $\frac{\textrm{Total number of maroon ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a maroon ONCE is 1/8.

Hence, the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) P(Picking a NOT whiten tie) = 1 - P( picking a white tie)

$= 1-(\frac{1}{8} ) = \frac{8-1}{8} = (\frac{7}{8} )$

So, the probability of NOT picking a white ONCE is 7/8.

Hence, the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

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