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3 years ago

How many minutes are in 3 hours and 10 minutes

2 answers:

galina1969 [7]3 years ago

7 0

1 hour = 60 minutes
Multiply 60 times 3
60*3 = 180
3 hours = 180 minutes
Then we add the 10 extra minutes.
So 3 hours and 10 minutes is 190 minutes.

Hope this helps you! (:
-Hamilton1757

mamaluj [8]3 years ago

6 0

190 min.................................

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Is -0.125374 irrational or rational?

Arisa [49]

Answer:

It's irrational because it's not repeating or terminating decimal.

Step-by-step explanation:

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2 years ago

Solve for w in the equation w⁄5 = 25

Anarel [89]

we are given

$\frac{w}{5} =25$

Since, we have to solve for w

so, we will isolate w on anyone side

Multiply both sides by 5

$5*\frac{w}{5} =5*25$

$w =5*25$

$w =125$

so,

option-D..........Answer

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3 years ago

Read 2 more answers

What’s the answer and work for this? Someone please telllllllll meeee!!!!

HACTEHA [7]

Answer: 25

Step-by-step explanation: The median is the average of the middle two numbers and if the median will be 17.5 then the sum of the middle numbers will be 35, and when we arrange the numbers in the least to greatest order we realize that 10 will be one of the middle two numbers when a number is added, and so the other number must be 25. Hope this helped!

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2 years ago

A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

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2 years ago

The table shows the amounts Doug spent on camping supplies. tent_$150.50

katrin2010 [14]

Answer:

Step-by-step explanation:

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2 years ago