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MariettaO [177]
3 years ago
12

Need help with this asap………

Mathematics
1 answer:
Iteru [2.4K]3 years ago
8 0

Answer:

y= 32

Step-by-step explanation:

HOPE THIS HELPS :)

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Write the expression: 3 divided by the sum of x and 9. A) 3 + 9 x B) x 3 + 9 C) x + 9 3 D) 3 x + 9
yuradex [85]
Yes that is the answer
8 0
3 years ago
Read 2 more answers
I need to answer this before 11:59 pm by today , i will give you 10 points!!!
Firdavs [7]

Answer:

For first part, t= 0.18 sec or 3.4 sec.

For second part, t= 3.7 sec.

Step by step answer:

First part:

Set h(t) = 17and solve for tt.

-16t²+ 58t + 7= 17

-16t² + 58t - 10 = 0

Solve this quadratic equation for t. You should get 2 positive solutions. The lower value is the time to reach 17 on the way up, and the higher value is the time to reach 17 again, on the way down.

Second part:

Set h(t) = 0 and solve the resulting quadratic equation for t. You should get a negative solution (which you can discard), and a positive solution. The latter is your answer.

7 0
3 years ago
(05.07 MC)
sp2606 [1]
Given that the net of the square pyramid is as shown above, the surface are of the pyramid will be given by:
SA=(number of triangles)*(area of triangle)*(area of square base)
area of one triangle will be:
A=1/2*base*height
A=1/2*0.8*0.75
A=0.3 sq. inches

area of the square base will be:
A=0.75*0.75
A=0.5625
Therefore the surface area will be:
SA=4*0.3*0.5625
SA=0.675 sq. inches
5 0
3 years ago
The perimeter of the quadrilateral below is 64 units.
Harrizon [31]

Answer:

a = 22

x = 96

y = 144

Step-by-step explanation:

In the given figure

∵ The figure is a quadrilateral

∵ Each two adjacent have the same mark

∴ Every two adjacent sides are equal

∵ The perimeter of the quadrilateral is the sum of its outline sides

∴ The perimeter of the quadrilateral = 10 + 10 + a + a

∴ The perimeter of the quadrilateral = 20 + 2a

∵ The perimeter of the quadrilateral = 64 units

→ Equate the right sides of the perimeter

∴ 20 + 2a = 64

→ Subtract 20 from both sides

∵ 20 -20 + 2a = 64 - 20

∴ 2a = 44

→ Divide both sides by 2 to find a

∴ a = 22

<em>If a line segment joins the vertex of measure y and the vertex of measure 24°, then it will divide the quadrilateral into 2 congruent triangles by the SSS case.</em>

→ Use the result of congruency to find x

∵ The opposite angles of measures x and 96° are equal

∴ x = 96

∵ The sum of the measures of the angle of a quadrilateral is 360°

∴ 96° + y° + 96° + 24° = 360°

→ Add the like terms on the left side

∵ (96 + 96 + 24) + y = 360

∴ 216 + y = 360

→ Subtract 216 from both sides

∵ 216 - 216 + y = 360 - 216

∴ y = 144

6 0
3 years ago
In ΔHIJ, h = 40 cm, ∠J=20° and ∠H=93°. Find the length of j, to the nearest centimeter.
DaniilM [7]

Given:

In ΔHIJ, h = 40 cm, ∠J=20° and ∠H=93°.

To find:

The length of j, to the nearest centimeter.

Solution:

According to Law of sine,

\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}

In ΔHIJ, using law of sine, we get

\dfrac{j}{\sin J}=\dfrac{h}{\sin H}

\dfrac{j}{\sin (20^\circ)}=\dfrac{40}{\sin (93^\circ)}}

j=\dfrac{40\times \sin (20^\circ)}{\sin (93^\circ)}}

On further simplification, we get

j=\dfrac{40\times 0.34202}{0.99863}

j=\dfrac{13.6808}{0.99863}

j=13.69958

Approximate the value to the nearest centimeter.

j\approx 14

Therefore, the length of j is 14 cm.

7 0
3 years ago
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