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MrMuchimi
2 years ago
15

Model With Mathematics During a football game, a kicker is called in twice to kick a field goal from the 30 yard line. Suppose t

hat for each attempt, the probability that he will make the field goal is 0.8.
a. What is the probability that he will make both field goals?

b. What is the probability that he will make neither field goal?​
Mathematics
1 answer:
Marizza181 [45]2 years ago
8 0

Answers:

  • (a) 0.64
  • (b) 0.04

============================================

Explanation:

Assuming each kick is independent of any other, this means the probability of making two field goals in a row is 0.8*0.8 = 0.64

The probability of missing any single field goal is 1-0.8 = 0.2; so the probability of missing two in a row is 0.2*0.2 = 0.04

----------------

Extra info:

Adding up those results shows that 0.64+0.04 = 0.68 is the probability of either making 2 in a row or missing 2 in a row; that leaves 1-0.68 = 0.32 to represent the probability of making exactly one field goal in either order.

Or you could note that 0.8*0.2+0.2*0.8 = 0.32

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Answer:

3 strain would still alive after 48 hours

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Formula : N(t)=N_0(1-r)^t

N_0=Initial population

N(t)= Population after t hours

r = rate of decrease = 18% = 0.18

t = time = 48 hours

So,the  strain would still be alive after 48 hours=40000(1-0.18)^{48}=2.91 \sim 3

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3 years ago
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anyanavicka [17]

Answer:

x =\dfrac{45 \sqrt{6}}{ 2}

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}

In order to estimate the point along the shore, x meters from B, the runner should  stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

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\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}

squaring both sides; we get

\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}

\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}

By cross multiplying; we get

49x^2 = 25(54^2+x^2)

49x^2 = 25 \times 54^2+ 25x^2

49x^2-25x^2 = 25 \times 54^2

24x^2 = 25 \times 54^2

x^2 = \dfrac{25 \times 54^2}{24}

x =\sqrt{ \dfrac{25 \times 54^2}{24}}

x =\dfrac{5 \times 54}{\sqrt{24}}

x =\dfrac{270}{\sqrt{4 \times 6}}

x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}

x =\dfrac{45 \sqrt{6}}{ 2}

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Answer:

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Step-by-step explanation:I’m sorry if I answered it too late

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