I don't know how to do this can you help me please?

Mathematics

1 answer:

DIA [1.3K]3 years ago

5 0

Answer:

Key characteristics include: intercepts; intervals where the function is increasing, decreasing, positive, or negative; relative maximums and minimums; symmetries; end behavior; and periodicity.

Step-by-step explanation:

I don't really know how to help on this but I hope of you know what key characteristics are you'll understand what to dom

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Solve for x and y in the system of equation 3x²+4y=17 2x²+5y=2 I'll mark brainliest

Novay_Z [31]

Answer:

$x=\pm \sqrt{11} \\y=-4.$

Step-by-step explanation:

$\left \{ {{3x^2+4y=17} \atop {2x^2+5y=2}} \right. \\\\Then\\\\\left \{ {{2 \times (3x^2+4y)=2 \times 17} \atop {3\times(2x^2+5y)=3\times2}} \right. \\\\\left \{ {{6x^2+8y=34 \quad (1)} \atop {6x^2+15y=6\quad (2)}} \right.\\\\(1)-(2) \Rightarrow -7y=28 \Rightarrow y =-4.\\Since \: \: 2x^2+5y=2 \Rightarrow 2x^2=2-5y\\\Rightarrow 2x^2=2+20=22\\\Rightarrow x^2=22:2=11\\\Rightarrow x=\pm \sqrt{11}.$

7 0

3 years ago

The area of a rectangular fountain is (x^2 + 12x +20) feet squared. The width is (x + 2) feet.

n200080 [17]

Part A:
The total area = x² + 12x + 20 = (x+2)(x+10)
The width = x+2
∴ Length = area / width = [ (x+2)(x+10) ] / (x+2) = x+10

Part B: 
A 2-foot walkway is built around the fountain

∴ The width = (x+2) + 2 + 2 = x + 6
The length = (x+10) + 2 + 2 = x +14

Part C:
the total area covered by the fountain and walkway. 
= (x+6)(x+14)
= x² + 20 x + 84

See the attache figure for more explanation

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4 years ago

WILL MARK BRAINLIEST!!! PLZ HELP! The following graph describes function 1, and the equation below it describes function 2. Dete

Assoli18 [71]

Answer:

Step-by-step explanation:

The maximum/minimum values is simply the y-value of the vertex. Since both of the functions have a negative leading coefficient, they will both have maximum values.

For Function 1, we can see that the vertex is at (4,1). Thus, it's maximum value is at y=1.

For Function 2, we need to work out the vertex. To do this we can use:

$x=\frac{-b}{2a} ,y=f(-b/2a)$