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Delvig [45]
3 years ago
6

The value (in cents) of the change in a purse that contains twice as many nickels as pennies, five more dimes than nickels, and

as many quarters as dimes and nickels combined;
p = number of pennies
Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0

Value of the pursue in cents: 131p+175

Step-by-step explanation:

Let's call:

p = number of pennies

The problem tells us that the pursue contains twice as many nickels as pennies, so the number of nickels is

n=2p

Also, the pursue contains five more dimes than nickels, so the number of dimes is

d=n+5=2p+5

And finally, the pursue contains as many quarters as dimes and nickels combained, so the number of quarters is

q=d+n=(2p+5)+2p=4p+5

The value of each type of coin is:

Penny: 1 cent

Nickel: 5 cents

Dime: 10 cents

Quarter: 25 cents

So, the total value of the pursue in cents is:

1p+5n+10d+25q

And substituting,

=p+5(2p)+10(2p+5)+25(4p+5)=\\p+10p+20p+50+100p+125=\\131p+175

So, this is the value of the change in the pursue in cents.

Learn more about expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

kap26 [50]3 years ago
8 0

Answer:

its d for online schoo

Step-by-step explanation:

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