The length of RS is 10 because it's a 3-4-5 right triangle
Answer:
(6c-7d)^2
Step-by-step explanation:
Factor using the perfect square rule
Answer:
x(x-5)(x-8)
or
x=5
x=8
Step-by-step explanation:
x(x^2-13x+40)
x(x-5) (x-8)
Answer:
(a)
(b)
(c)
(d)
(e)
(f)
Step-by-step explanation:
Let as consider the given equations are
.
(a)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(b)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(c)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(d)

![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(e)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(f)


![[\because \log10^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog10%5Ex%3Dx%5D)
Step-by-step explanation (Question 1):
<u>Step 1: (Question 1): Subtract x from both sides.</u>
5x+3=x+13
5x+3−x=x+13−x
4x+3=13
<u>Step 2: (Question 1): Subtract 3 from both sides.</u>
4x+3−3=13−3
4x=10
<u>Step 3: (Question 1): Divide both sides by 4.</u>
4x/4 = 10/4
FIRST ANSWER: x = 5/2
Step-by-step explanation (Question 2):
<u>Step 1: (Question 2): Multiply by LCM</u>
15x^2 - 6 = x
<u>Step 2: (Question 2): Solve 15x^2</u>
15x^2 - 6 = x:
x = 2/3
x = -3/5
<u>Step 3: (Question 2): Solve</u>
ANSWER: x=0.666667 or x=−0.6
See Attachment 1 for question 1 steps (FULL)
See Attachment 2 for question 2 steps (FULL)
Answer:
1) x = 5/2
2) x=0.666667 or x=−0.6
Hope this helps.