Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
<span>A) x+y+z=23
B) y+z=14
C) z=9
Since z = 9 then
A) x + y = 14
B) y = 5
A) </span><span><span>x + y+ z=23</span>
A) x + 5 + 9 = 23
A) x = 9
</span>
Answer:
17/8
Step-by-step explanation:
2/1=2
11-2-6-7/8
9-6-7/8
3-7/8
24/8-7/8
17/8
Answer:
(x + 14)² + (y – 21/2)² = 1
Step-by-step explanation:
The equation of a circle can be written as seen below
(x – h)² + (y – k)² = r²
Where (h,k) is at the center and r = radius
We are given that the radius is 1
We are also given that the center is at (-14,21/2)
So we know that r = 1, h = -14, and k = 21/2
So to find the equation of the circle we simply substitute these values into the equation of a circle
Equation of a circle: (x – h)² + (y – k)² = r²
r = 1, h = -14, and k = 21/2
Substitute values
(x – (-14))² + (y – 21/2)² = 1²
1^2 = 1
The two negative signs before the 14 cancel out and it changes to + 14
The equation of a circle with a center at (-14,21/2) and a radius of 1 is (x + 14)² + (y – 21/2)² = 1
Writing an equation is the easiest way to figure this out.
b = boys, g = girlsb = 3/4g35 students = g + b35 = g + 3/4g35 = 7/4g35/7/4 = g20 girls35 - 20 = b or 3/4(35) = b15 boys
