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1 year ago

Question 1 Find the Mean of the following set of data values. 46, 57, 68, 63, 49, 52, 61, 68

1 answer:

3 0

The mean would be 58!! Basically what you’re doing to get the mean is adding all of the numbers together and dividing by how many you’re adding. In this case, you would add all of the numbers and divide by 8 because you have 8 numbers ! :D

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Write an equation for the quadratic graphed below

uranmaximum [27]

Answer:

Step-by-step explanation:

LOL The graph doesn’t match the y intercept :)

Anyway

If we have point (0,-3) we have a quadratic of

y=ax^2+bx-3 we are given points (-1,0) and (2,0) so

a-b-3=0 and 4a+2b-3=0

4a+2b-3+2(a-b-3)=0

4a+2b-3+2a-2b-6=0

6a-9=0

6a=9

a=1.5, since a-b=3

1.5-b=3

b=-1.5

y=1.5x^2-1.5x-3

6 0

2 years ago

Read 2 more answers

How to convert 1500 ml to liters

Zepler [3.9K]

Divide 1500 by 1000
1500/1000 = 1.5

4 0

2 years ago

The woodlands middle school poll results show that about 79.3% of people who prefer pizza are students and about 81% of people w

vazorg [7]

Answer: A: there is not enough evidence to support a relationship between lunch preference and role at school

6 0

2 years ago

Read 2 more answers

Gerry has 50 sport trading cards. of those, 1/5 of them are baseball cards, 1/10 of them are football cards, and the rest are ba

emmainna [20.7K]

1/5=10 There are 10 baseball cards 1/10=5 There are 5 football card's 50-10-5=35 There are 35 basketball card's 35-10=25 Gerry has 25 more basketball card's than baseball card's

7 0

2 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

2 years ago