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2 years ago

Help please!!

Mathematics

1 answer:

yanalaym [24]2 years ago

8 0

Answer: (1,-1)

Step-by-step explanation:

Midpoint of BC=(6+4)/2, (3–1)/2. =(5,1)

Slope of BC is (3+1)/4–6)= 4/-2 = -2

Slope of perpendicular bisector of BC =+1/2

Eqn of perpendicular bisector is : Y-1 =1/2 (x-5)

Y=1/2 •(x-5) +1

Midpoint of AB. (6–2)/2, (3–1)/2 ={2,1)

Slope of AB is(3+1)/(-2–6) = 4/-8 =-1/2

Slope of perpendicular bisector = +2

Eqn of perpendicular bisector is Y-1. =2( X-2)

Y=2X-4+1 = 2X -3

Solving Y=(X-5)/2 +1

& Y=2X-3

2X-3 =(x-5/2)+1

2X-4 =(x-5/2)

4X-8 = x-5

3X =3

X=1

Y= 2×1–3= -1

Circumcentre is(1,-1)

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