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2 years ago

Four movie tickets cost $26.00 . How much do seven movie tickets cost?

Mathematics

1 answer:

sashaice [31]2 years ago

7 0

Answer:

Hi! I suggest reading the explanation, it will help make this equation more simple.

↓↓↓

The answer is $45.50

Step-by-step explanation:

First, divide 26.00 by four. This will give you 6.5, so now you know that each ticket individually costs $6.5 or $6.50.

next, multiple 6.50 by 7.

this will give you 45.5 or $45.50.

double check your answer by dividing 45.50 by 7.

your answer should be 6.5 on a calculator.

that's all! hope this helped.

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Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x

fredd [130]

Answer:

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

$6\cdot x^{2} \geq 10 + 11\cdot x$

$6\cdot x^{2}-11\cdot x -10 \geq 0$

$6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0$

Roots are found by Quadratic Formula:

$r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}$

$r_{1} = \frac{5}{2}$ and $r_{2} = -\frac{2}{3}$

Then, the factorized form of the inequation is:

$6\cdot \left(x-\frac{5}{2}\right)\cdot \left(x+\frac{2}{3} \right)\geq 0$

By Real Algebra, there are two condition that fulfill the inequation:

a) $x-\frac{5}{2} \geq 0 \,\wedge\,x+\frac{2}{3}\geq 0$

$x \geq \frac{5}{2}\,\wedge\,x \geq-\frac{2}{3}$

$x \geq \frac{5}{2}$

b) $x-\frac{5}{2} \leq 0 \,\wedge\,x+\frac{2}{3}\leq 0$

$x \leq \frac{5}{2}\,\wedge\,x\leq-\frac{2}{3}$

$x\leq -\frac{2}{3}$

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

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Assume that X is normally distributed with a mean of 20 and a standard deviation of 2. Determine the following. (a) P(X 24) (b)

Tems11 [23]

Answer:

a) P( X < 24 ) = 0.9772

b) P ( X > 18 ) =0.8413

c) P ( 14 < X < 26) = 0.9973

d) P ( 14 < X < 26) = 0.9973

e) P ( 16 < X < 20) = 0.4772

f) P ( 20 < X < 26) = 0.4987

Step-by-step explanation:

Given:

- Mean of the distribution u = 20

- standard deviation sigma = 2

Find:

a. P ( X < 24 )

b. P ( X > 18 )

c. P ( 18 < X < 22 )

d. P ( 14 < X < 26 )

e. P ( 16 < X < 20 )

f. P ( 20 < X < 26 )

Solution:

- We will declare a random variable X that follows a normal distribution

X ~ N ( 20 , 2 )

- After defining our variable X follows a normal distribution. We can compute the probabilities as follows:

a) P ( X < 24 ) ?

- Compute the Z-score value as follows:

Z = (24 - 20) / 2 = 2

- Now use the Z-score tables and look for z = 2:

P( X < 24 ) = P ( Z < 2) = 0.9772

b) P ( X > 18 ) ?