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2 years ago

Help wanted will mark brainiest

Mathematics

1 answer:

Sedbober [7]2 years ago

7 0

Answer:

For question a the answer is option b at 50$

For question b the answer is 50 miles and option a is less

Step-by-step explanation:

You might be interested in

1. What is the solution to the system of equations graphed below? (1 point)

xenn [34]

Answer:

The answer is B

Step-by-step explanation:

lol i had the same question

5 0

3 years ago

Use the graph below to fill in the blank with the correct number:

Alik [6]

Let
$A(-3,0) \\ B(-2,2) \\ C(0,1) \\ D(1,-2)$

we know that

Point A
$A(-3,0) \\ for x=-3 \\ f(-3)=0$

Point B
$B(-2,2) \\ for x=-2 \\ f(-2)=2$

Point C
$C(0,1) \\ for x=0 \\ f(0)=1$

Point D
$D(1,-2) \\ for x=1 \\ f(1)=-2$

therefore

the answer is
$f(0)=1$

4 0

3 years ago

Read 2 more answers

(a) A survey of the adults in a town shows that 8% have liver problems. Of these, it is also found that 25% are heavy drinkers,

jekas [21]

Answer:

The probability that the selected adult has liver problems is 0.08

Step-by-step explanation:

In this question, from the data given, we want to calculate the probability that an adult selected at random has liver problems.

Let E(L) be the event that an adult has liver problems.

The probability is directly obtainable from the question and it is given as 8%

Thus, the probability that the selected adult has liver problems; P(L) = 8% = 8/100 = 0.08

3 0

3 years ago

Given the circle with the diameter of 33 cm find the area of the circle

exis [7]

Answer:

51.81 cm^2

Step-by-step explanation:

Find The Half Of 33 which is 16.5

Use The Formula For Area

A= $\pi$ x r^2

A= 3.14 x 16.5

A= 51.81 cm^2

3 0

2 years ago

If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0

3 years ago