Answer:
A)The required linear demand equation ( q ) = -4500p + 41500
B) $4.61
    $95680.55
C) No it would not have been possible by charging a suitable price 
Step-by-step explanation:
<u>A)  find the linear demand equation</u>
given two points ; ( 3, 28000 ) and ( 5, 19000 )
slope ( m ) = ( y2 - y1 ) / ( x2 - x1 ) 
                  = ( 19000 - 28000 ) / ( 5 - 3 )  = -4500
slope intercept is represented as ; y = mx + b 
where y( 28000) = -4500(3) + b 
   hence b = 41500  
hence ; y = -4500x + 41500
The required linear demand equation ( q ) = -4500p + 41500   ----- ( 1 )
p = price per ride
<u>B ) Determine the price the company should charge to maximize revenue from ridership  and corresponding daily revenue</u>
Total revenue ( R ) = qp
                                = p ( -4500p + 41500 )
   hence R = -4500p^2 + 41500p  ------ ( 2 )
To determine the price that should maximize revenue from ridership we will equate R = -4500p^2 + 41500p  to a quadratic equation R(p) = ap^2 + bp + c 
where a = -4500 ,  b = 41500 , c = 0
hence p =  =
  =  =  4.61
 =  4.61 
$4.61 is the price the company should charge to maximize revenue from ridership
corresponding daily revenue = R = -4500p^2 + 41500 p 
where p = $4.61 
hence R = -4500(4.61 )^2 + 41500(4.61) =  $95680.55
C) No it would not have been possible by charging a suitable price